m^2+n^2=6n-4m-13,则m^2-n^2=?(要求过程)谢谢
来源:百度知道 编辑:UC知道 时间:2024/05/29 04:31:58
解:
m^2+n^2=6n-4m-13
m^2+4m+n^2-6n+13=0
(m^2+4m+4)+(n^2-6n+9)=0
(m+2)^2+(n-3)^2=0
m=-2 n=3
m^2-n^2=(-2)^2-3^2
= 4-9
=-5
m^2+n^2=6n-4m-13
(m-3)^2+(n+2)^2=0
m=3,n=-2
m^2-n^2=5
m^2+n^2=6n-4m-13
m^2+4m+4+n^2-6n+9=0
(m+2)^2+(n-3)^2=0
m=-2,n=3
m^2+n^2-6n+4m+13=0
m^2+4m+4+n^2-6n+9=0
(m+2)^2+(n-3)^2=0
得:m=-2,n=3
m^2-n^2=4-9=-5
m^2-n^2=-5
多看书 这种问题还需要问?are you kidding?
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